Base | Representation |
---|---|
bin | 1001000011011110010… |
… | …0000100100010101011 |
3 | 112212111121200211002001 |
4 | 2100313210010202223 |
5 | 10022032030302243 |
6 | 155243102151431 |
7 | 14144461620361 |
oct | 2206744044253 |
9 | 485447624061 |
10 | 155551025323 |
11 | 5aa72553691 |
12 | 26191882577 |
13 | 1188c61a125 |
14 | 7758acb631 |
15 | 40a60cca4d |
hex | 24379048ab |
155551025323 has 2 divisors, whose sum is σ = 155551025324. Its totient is φ = 155551025322.
The previous prime is 155551025309. The next prime is 155551025353. The reversal of 155551025323 is 323520155551.
It is a weak prime.
It is an emirp because it is prime and its reverse (323520155551) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 155551025323 - 213 = 155551017131 is a prime.
It is a super-2 number, since 2×1555510253232 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (155551025303) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77775512661 + 77775512662.
It is an arithmetic number, because the mean of its divisors is an integer number (77775512662).
Almost surely, 2155551025323 is an apocalyptic number.
155551025323 is a deficient number, since it is larger than the sum of its proper divisors (1).
155551025323 is an equidigital number, since it uses as much as digits as its factorization.
155551025323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 112500, while the sum is 37.
The spelling of 155551025323 in words is "one hundred fifty-five billion, five hundred fifty-one million, twenty-five thousand, three hundred twenty-three".
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