Base | Representation |
---|---|
bin | 100011011000101110110111… |
… | …001011100110001011010001 |
3 | 202102001012100211122220112110 |
4 | 203120232313023212023101 |
5 | 130344330211042203131 |
6 | 1310555554203015533 |
7 | 44531661355426356 |
oct | 4330566713461321 |
9 | 672035324586473 |
10 | 155631213241041 |
11 | 4565291063929a |
12 | 1555645650a5a9 |
13 | 68abc64101a75 |
14 | 2a6083b66a62d |
15 | 12ed4d1d9b646 |
hex | 8d8bb72e62d1 |
155631213241041 has 32 divisors (see below), whose sum is σ = 220118377236480. Its totient is φ = 97471653864704.
The previous prime is 155631213240983. The next prime is 155631213241061. The reversal of 155631213241041 is 140142312136551.
It is a cyclic number.
It is not a de Polignac number, because 155631213241041 - 213 = 155631213232849 is a prime.
It is not an unprimeable number, because it can be changed into a prime (155631213241061) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 76256686 + ... + 78270968.
It is an arithmetic number, because the mean of its divisors is an integer number (6878699288640).
Almost surely, 2155631213241041 is an apocalyptic number.
It is an amenable number.
155631213241041 is a deficient number, since it is larger than the sum of its proper divisors (64487163995439).
155631213241041 is a wasteful number, since it uses less digits than its factorization.
155631213241041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2017085.
The product of its (nonzero) digits is 86400, while the sum is 39.
Adding to 155631213241041 its reverse (140142312136551), we get a palindrome (295773525377592).
The spelling of 155631213241041 in words is "one hundred fifty-five trillion, six hundred thirty-one billion, two hundred thirteen million, two hundred forty-one thousand, forty-one".
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