Base | Representation |
---|---|
bin | 10110101010110011100… |
… | …110011010100101110001 |
3 | 12111220221011021001122111 |
4 | 112222303212122211301 |
5 | 201010324041300301 |
6 | 3151350043005321 |
7 | 220355344011526 |
oct | 26526346324561 |
9 | 5456834231574 |
10 | 1557791353201 |
11 | 550723675416 |
12 | 211ab1209841 |
13 | b3b8c4054a5 |
14 | 5557ca7114d |
15 | 2a7c5c73551 |
hex | 16ab399a971 |
1557791353201 has 2 divisors, whose sum is σ = 1557791353202. Its totient is φ = 1557791353200.
The previous prime is 1557791353147. The next prime is 1557791353247. The reversal of 1557791353201 is 1023531977551.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1169045338176 + 388746015025 = 1081224^2 + 623495^2 .
It is an emirp because it is prime and its reverse (1023531977551) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1557791353201 - 225 = 1557757798769 is a prime.
It is not a weakly prime, because it can be changed into another prime (1557791353301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 778895676600 + 778895676601.
It is an arithmetic number, because the mean of its divisors is an integer number (778895676601).
Almost surely, 21557791353201 is an apocalyptic number.
It is an amenable number.
1557791353201 is a deficient number, since it is larger than the sum of its proper divisors (1).
1557791353201 is an equidigital number, since it uses as much as digits as its factorization.
1557791353201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 992250, while the sum is 49.
The spelling of 1557791353201 in words is "one trillion, five hundred fifty-seven billion, seven hundred ninety-one million, three hundred fifty-three thousand, two hundred one".
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