Base | Representation |
---|---|
bin | 1001000100111100001… |
… | …1111111111110101011 |
3 | 112220112002112120202121 |
4 | 2101033003333332223 |
5 | 10023333442134321 |
6 | 155350144212111 |
7 | 14160316635322 |
oct | 2211703777653 |
9 | 486462476677 |
10 | 155945271211 |
11 | 60155049434 |
12 | 2628190a037 |
13 | 119231c5612 |
14 | 77951d50b9 |
15 | 40caa06441 |
hex | 244f0fffab |
155945271211 has 2 divisors, whose sum is σ = 155945271212. Its totient is φ = 155945271210.
The previous prime is 155945271203. The next prime is 155945271217. The reversal of 155945271211 is 112172549551.
It is a strong prime.
It is an emirp because it is prime and its reverse (112172549551) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 155945271211 - 23 = 155945271203 is a prime.
It is a super-2 number, since 2×1559452712112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (155945271217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 77972635605 + 77972635606.
It is an arithmetic number, because the mean of its divisors is an integer number (77972635606).
Almost surely, 2155945271211 is an apocalyptic number.
155945271211 is a deficient number, since it is larger than the sum of its proper divisors (1).
155945271211 is an equidigital number, since it uses as much as digits as its factorization.
155945271211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 126000, while the sum is 43.
The spelling of 155945271211 in words is "one hundred fifty-five billion, nine hundred forty-five million, two hundred seventy-one thousand, two hundred eleven".
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