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1564461122113 = 13711419424249
BaseRepresentation
bin10110110001000001001…
…001100100001001000001
312112120010222121102112201
4112301001021210021001
5201113004021401423
63154411543153201
7221012543061121
oct26610111441101
95476128542481
101564461122113
1155353657752a
12213252a45801
13b46b3187406
1455a127c8c81
152aa665ab2ad
hex16c41264241

1564461122113 has 4 divisors (see below), whose sum is σ = 1575880546500. Its totient is φ = 1553041697728.

The previous prime is 1564461122053. The next prime is 1564461122117. The reversal of 1564461122113 is 3112211644651.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1097566331904 + 466894790209 = 1047648^2 + 683297^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1564461122113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1564461122117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5709711988 + ... + 5709712261.

It is an arithmetic number, because the mean of its divisors is an integer number (393970136625).

Almost surely, 21564461122113 is an apocalyptic number.

It is an amenable number.

1564461122113 is a deficient number, since it is larger than the sum of its proper divisors (11419424387).

1564461122113 is a wasteful number, since it uses less digits than its factorization.

1564461122113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11419424386.

The product of its digits is 34560, while the sum is 37.

Adding to 1564461122113 its reverse (3112211644651), we get a palindrome (4676672766764).

The spelling of 1564461122113 in words is "one trillion, five hundred sixty-four billion, four hundred sixty-one million, one hundred twenty-two thousand, one hundred thirteen".

Divisors: 1 137 11419424249 1564461122113