Base | Representation |
---|---|
bin | 11101001101001100… |
… | …10101100010100001 |
3 | 1111110202121222101221 |
4 | 32212212111202201 |
5 | 224103033010231 |
6 | 11111524055041 |
7 | 1063364353423 |
oct | 164646254241 |
9 | 44422558357 |
10 | 15679969441 |
11 | 6716a30134 |
12 | 3057234481 |
13 | 162b694136 |
14 | a8a666813 |
15 | 61b87bd11 |
hex | 3a69958a1 |
15679969441 has 2 divisors, whose sum is σ = 15679969442. Its totient is φ = 15679969440.
The previous prime is 15679969411. The next prime is 15679969457. The reversal of 15679969441 is 14496997651.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11643273216 + 4036696225 = 107904^2 + 63535^2 .
It is an emirp because it is prime and its reverse (14496997651) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 15679969441 - 213 = 15679961249 is a prime.
It is a super-2 number, since 2×156799694412 (a number of 21 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 15679969441.
It is not a weakly prime, because it can be changed into another prime (15679969411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7839984720 + 7839984721.
It is an arithmetic number, because the mean of its divisors is an integer number (7839984721).
Almost surely, 215679969441 is an apocalyptic number.
It is an amenable number.
15679969441 is a deficient number, since it is larger than the sum of its proper divisors (1).
15679969441 is an equidigital number, since it uses as much as digits as its factorization.
15679969441 is an evil number, because the sum of its binary digits is even.
The product of its digits is 14696640, while the sum is 61.
The spelling of 15679969441 in words is "fifteen billion, six hundred seventy-nine million, nine hundred sixty-nine thousand, four hundred forty-one".
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