Base | Representation |
---|---|
bin | 11101001101010111… |
… | …11011001000011001 |
3 | 1111110212101101120221 |
4 | 32212223323020121 |
5 | 224103421343022 |
6 | 11112015320041 |
7 | 1063412663605 |
oct | 164653731031 |
9 | 44425341527 |
10 | 15681434137 |
11 | 6717840626 |
12 | 3057820021 |
13 | 162ba87a15 |
14 | a8a928505 |
15 | 61ba6acc7 |
hex | 3a6afb219 |
15681434137 has 2 divisors, whose sum is σ = 15681434138. Its totient is φ = 15681434136.
The previous prime is 15681434047. The next prime is 15681434173. The reversal of 15681434137 is 73143418651.
Together with next prime (15681434173) it forms an Ormiston pair, because they use the same digits, order apart.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10187066761 + 5494367376 = 100931^2 + 74124^2 .
It is a cyclic number.
It is not a de Polignac number, because 15681434137 - 27 = 15681434009 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 15681434093 and 15681434102.
It is not a weakly prime, because it can be changed into another prime (15681464137) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7840717068 + 7840717069.
It is an arithmetic number, because the mean of its divisors is an integer number (7840717069).
Almost surely, 215681434137 is an apocalyptic number.
It is an amenable number.
15681434137 is a deficient number, since it is larger than the sum of its proper divisors (1).
15681434137 is an equidigital number, since it uses as much as digits as its factorization.
15681434137 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 241920, while the sum is 43.
The spelling of 15681434137 in words is "fifteen billion, six hundred eighty-one million, four hundred thirty-four thousand, one hundred thirty-seven".
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