Base | Representation |
---|---|
bin | 1001010000001011011… |
… | …1111110001100010011 |
3 | 120012022100002011001201 |
4 | 2110002313332030103 |
5 | 10101023234021133 |
6 | 201005351412031 |
7 | 14325140564554 |
oct | 2240267761423 |
9 | 505270064051 |
10 | 158962017043 |
11 | 61462a07205 |
12 | 26984084017 |
13 | 11cb41c101b |
14 | 799db1a32b |
15 | 42057a6d7d |
hex | 2502dfe313 |
158962017043 has 2 divisors, whose sum is σ = 158962017044. Its totient is φ = 158962017042.
The previous prime is 158962017023. The next prime is 158962017077. The reversal of 158962017043 is 340710269851.
158962017043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 158962017043 - 29 = 158962016531 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 158962016984 and 158962017002.
It is not a weakly prime, because it can be changed into another prime (158962017023) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 79481008521 + 79481008522.
It is an arithmetic number, because the mean of its divisors is an integer number (79481008522).
It is a 1-persistent number, because it is pandigital, but 2⋅158962017043 = 317924034086 is not.
Almost surely, 2158962017043 is an apocalyptic number.
158962017043 is a deficient number, since it is larger than the sum of its proper divisors (1).
158962017043 is an equidigital number, since it uses as much as digits as its factorization.
158962017043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 362880, while the sum is 46.
The spelling of 158962017043 in words is "one hundred fifty-eight billion, nine hundred sixty-two million, seventeen thousand, forty-three".
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