Base | Representation |
---|---|
bin | 1110100011010100110110… |
… | …0111110001011110111011 |
3 | 2002122120221101002221011221 |
4 | 3220311031213301132323 |
5 | 4044121103143341111 |
6 | 54010153552332511 |
7 | 3240652201231066 |
oct | 350651547613673 |
9 | 62576841087157 |
10 | 16000055449531 |
11 | 51096491a952a |
12 | 1964b02244137 |
13 | 8c0a4cb30c9a |
14 | 3d459a4338dd |
15 | 1cb2e8bd0371 |
hex | e8d4d9f17bb |
16000055449531 has 2 divisors, whose sum is σ = 16000055449532. Its totient is φ = 16000055449530.
The previous prime is 16000055449513. The next prime is 16000055449561. The reversal of 16000055449531 is 13594455000061.
Together with previous prime (16000055449513) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16000055449531 - 217 = 16000055318459 is a prime.
It is a super-2 number, since 2×160000554495312 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16000055449561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8000027724765 + 8000027724766.
It is an arithmetic number, because the mean of its divisors is an integer number (8000027724766).
Almost surely, 216000055449531 is an apocalyptic number.
16000055449531 is a deficient number, since it is larger than the sum of its proper divisors (1).
16000055449531 is an equidigital number, since it uses as much as digits as its factorization.
16000055449531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 16000055449531 in words is "sixteen trillion, fifty-five million, four hundred forty-nine thousand, five hundred thirty-one".
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