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16001403625153 = 123047913004207
BaseRepresentation
bin1110100011011001110111…
…1110101001111011000001
32002122201102022221100110101
43220312131332221323001
54044131333312001103
654010535432402401
73241030461440212
oct350663576517301
962581368840411
1016001403625153
11510a180210861
121965219846401
138c0c06235b3b
143d46874d5409
151cb377239a1d
hexe8d9dfa9ec1

16001403625153 has 4 divisors (see below), whose sum is σ = 16001417859840. Its totient is φ = 16001389390468.

The previous prime is 16001403625127. The next prime is 16001403625201. The reversal of 16001403625153 is 35152630410061.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16001403625153 - 25 = 16001403625121 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16001403625253) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5271625 + ... + 7732582.

It is an arithmetic number, because the mean of its divisors is an integer number (4000354464960).

Almost surely, 216001403625153 is an apocalyptic number.

It is an amenable number.

16001403625153 is a deficient number, since it is larger than the sum of its proper divisors (14234687).

16001403625153 is a wasteful number, since it uses less digits than its factorization.

16001403625153 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14234686.

The product of its (nonzero) digits is 64800, while the sum is 37.

The spelling of 16001403625153 in words is "sixteen trillion, one billion, four hundred three million, six hundred twenty-five thousand, one hundred fifty-three".

Divisors: 1 1230479 13004207 16001403625153