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16020442513 = 47340860479
BaseRepresentation
bin11101110101110010…
…01000110110010001
31112100111021210122201
432322321020312101
5230302213130023
611205405403201
71105000341325
oct167271106621
945314253581
1016020442513
116881138639
123131269501
131684092baa
14abd973985
1563b6d2bad
hex3bae48d91

16020442513 has 4 divisors (see below), whose sum is σ = 16361303040. Its totient is φ = 15679581988.

The previous prime is 16020442511. The next prime is 16020442583. The reversal of 16020442513 is 31524402061.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 16020442513 - 21 = 16020442511 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (16020442511) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 170430193 + ... + 170430286.

It is an arithmetic number, because the mean of its divisors is an integer number (4090325760).

Almost surely, 216020442513 is an apocalyptic number.

It is an amenable number.

16020442513 is a deficient number, since it is larger than the sum of its proper divisors (340860527).

16020442513 is an equidigital number, since it uses as much as digits as its factorization.

16020442513 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 340860526.

The product of its (nonzero) digits is 5760, while the sum is 28.

Adding to 16020442513 its reverse (31524402061), we get a palindrome (47544844574).

The spelling of 16020442513 in words is "sixteen billion, twenty million, four hundred forty-two thousand, five hundred thirteen".

Divisors: 1 47 340860479 16020442513