160485233 has 4 divisors (see below), whose sum is σ = 165662208. Its totient is φ = 155308260.

The previous prime is 160485209. The next prime is 160485257. The reversal of 160485233 is 332584061.

160485233 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 332584061 = 181 ⋅1837481.

It is an interprime number because it is at equal distance from previous prime (160485209) and next prime (160485257).

It is a cyclic number.

It is not a de Polignac number, because 160485233 - 2⁸ = 160484977 is a prime.

It is a super-2 number, since 2×160485233² = 51511020022128578, which contains 22 as substring.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 160485233.

It is not an unprimeable number, because it can be changed into a prime (160485203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2588441 + ... + 2588502.

It is an arithmetic number, because the mean of its divisors is an integer number (41415552).

Almost surely, 2^160485233 is an apocalyptic number.

It is an amenable number.

160485233 is a deficient number, since it is larger than the sum of its proper divisors (5176975).

160485233 is an equidigital number, since it uses as much as digits as its factorization.

160485233 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5176974.

The product of its (nonzero) digits is 17280, while the sum is 32.

The square root of 160485233 is about 12668.2766389119. The cubic root of 160485233 is about 543.4317715514.

The spelling of 160485233 in words is "one hundred sixty million, four hundred eighty-five thousand, two hundred thirty-three".