Base | Representation |
---|---|
bin | 10111011000110000100… |
… | …000000010010000111001 |
3 | 12200122021202101211202011 |
4 | 113120300200002100321 |
5 | 202312401124113303 |
6 | 3230150033005521 |
7 | 224053134060256 |
oct | 27306040022071 |
9 | 5618252354664 |
10 | 1607131472953 |
11 | 56a642900696 |
12 | 21b5810b38a1 |
13 | b8723542016 |
14 | 57add8ac42d |
15 | 2bc1271d16d |
hex | 17630802439 |
1607131472953 has 2 divisors, whose sum is σ = 1607131472954. Its totient is φ = 1607131472952.
The previous prime is 1607131472893. The next prime is 1607131472957. The reversal of 1607131472953 is 3592741317061.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1594229466384 + 12902006569 = 1262628^2 + 113587^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1607131472953 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1607131472897 and 1607131472906.
It is not a weakly prime, because it can be changed into another prime (1607131472957) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 803565736476 + 803565736477.
It is an arithmetic number, because the mean of its divisors is an integer number (803565736477).
Almost surely, 21607131472953 is an apocalyptic number.
It is an amenable number.
1607131472953 is a deficient number, since it is larger than the sum of its proper divisors (1).
1607131472953 is an equidigital number, since it uses as much as digits as its factorization.
1607131472953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 952560, while the sum is 49.
The spelling of 1607131472953 in words is "one trillion, six hundred seven billion, one hundred thirty-one million, four hundred seventy-two thousand, nine hundred fifty-three".
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