Base | Representation |
---|---|
bin | 10111011010000010110… |
… | …110011110010001100001 |
3 | 12200202212001011002022112 |
4 | 113122002312132101201 |
5 | 202323213322232221 |
6 | 3230535105445105 |
7 | 224132311434263 |
oct | 27320266362141 |
9 | 5622761132275 |
10 | 1608513086561 |
11 | 570191781417 |
12 | 21b8a7940795 |
13 | b88b3853974 |
14 | 57bd1195b33 |
15 | 2bc93b8015b |
hex | 17682d9e461 |
1608513086561 has 2 divisors, whose sum is σ = 1608513086562. Its totient is φ = 1608513086560.
The previous prime is 1608513086527. The next prime is 1608513086599. The reversal of 1608513086561 is 1656803158061.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1385048888161 + 223464198400 = 1176881^2 + 472720^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1608513086561 is a prime.
It is a super-3 number, since 3×16085130865613 (a number of 38 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1608513086461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 804256543280 + 804256543281.
It is an arithmetic number, because the mean of its divisors is an integer number (804256543281).
Almost surely, 21608513086561 is an apocalyptic number.
It is an amenable number.
1608513086561 is a deficient number, since it is larger than the sum of its proper divisors (1).
1608513086561 is an equidigital number, since it uses as much as digits as its factorization.
1608513086561 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1036800, while the sum is 50.
The spelling of 1608513086561 in words is "one trillion, six hundred eight billion, five hundred thirteen million, eighty-six thousand, five hundred sixty-one".
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