Base | Representation |
---|---|
bin | 1001010111110001110… |
… | …0111011100001001001 |
3 | 120101120111012020200012 |
4 | 2111330130323201021 |
5 | 10114212421423203 |
6 | 201544014121305 |
7 | 14426526165632 |
oct | 2257434734111 |
9 | 511514166605 |
10 | 161001748553 |
11 | 6230a320728 |
12 | 272531b0235 |
13 | 1224a969949 |
14 | 7b14998889 |
15 | 42c48b6bd8 |
hex | 257c73b849 |
161001748553 has 4 divisors (see below), whose sum is σ = 161011324368. Its totient is φ = 160992172740.
The previous prime is 161001748519. The next prime is 161001748559. The reversal of 161001748553 is 355847100161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 161001748553 - 218 = 161001486409 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 161001748553.
It is not an unprimeable number, because it can be changed into a prime (161001748559) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4762643 + ... + 4796328.
It is an arithmetic number, because the mean of its divisors is an integer number (40252831092).
Almost surely, 2161001748553 is an apocalyptic number.
It is an amenable number.
161001748553 is a deficient number, since it is larger than the sum of its proper divisors (9575815).
161001748553 is an equidigital number, since it uses as much as digits as its factorization.
161001748553 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9575814.
The product of its (nonzero) digits is 100800, while the sum is 41.
The spelling of 161001748553 in words is "one hundred sixty-one billion, one million, seven hundred forty-eight thousand, five hundred fifty-three".
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