Base | Representation |
---|---|
bin | 10111011100110101001… |
… | …011111011010110111001 |
3 | 12201001120120001211122101 |
4 | 113130311023323112321 |
5 | 202400330243231121 |
6 | 3232152030023401 |
7 | 224266411646641 |
oct | 27346513732671 |
9 | 5631516054571 |
10 | 1611505055161 |
11 | 571487656741 |
12 | 2203a1947b61 |
13 | b8c6c6856a1 |
14 | 57dd66ab521 |
15 | 2bdbb689491 |
hex | 177352fb5b9 |
1611505055161 has 4 divisors (see below), whose sum is σ = 1617632451072. Its totient is φ = 1605377659252.
The previous prime is 1611505055143. The next prime is 1611505055233. The reversal of 1611505055161 is 1615505051161.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1611505055161 - 217 = 1611504924089 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 1611505055161.
It is not an unprimeable number, because it can be changed into a prime (1611505055261) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3063697561 + ... + 3063698086.
It is an arithmetic number, because the mean of its divisors is an integer number (404408112768).
Almost surely, 21611505055161 is an apocalyptic number.
It is an amenable number.
1611505055161 is a deficient number, since it is larger than the sum of its proper divisors (6127395911).
1611505055161 is an equidigital number, since it uses as much as digits as its factorization.
1611505055161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6127395910.
The product of its (nonzero) digits is 22500, while the sum is 37.
The spelling of 1611505055161 in words is "one trillion, six hundred eleven billion, five hundred five million, fifty-five thousand, one hundred sixty-one".
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