Base | Representation |
---|---|
bin | 1001011000011100100… |
… | …1001001001110101011 |
3 | 120102000222200210222121 |
4 | 2112013021021032223 |
5 | 10120044331024321 |
6 | 202013502332111 |
7 | 14434134561061 |
oct | 2260711111653 |
9 | 512028623877 |
10 | 161181111211 |
11 | 623a159852a |
12 | 272a328a037 |
13 | 12278b796b3 |
14 | 7b30728031 |
15 | 42d54e6441 |
hex | 25872493ab |
161181111211 has 2 divisors, whose sum is σ = 161181111212. Its totient is φ = 161181111210.
The previous prime is 161181111193. The next prime is 161181111307. The reversal of 161181111211 is 112111181161.
It is a m-pointer prime, because the next prime (161181111307) can be obtained adding 161181111211 to its product of digits (96).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 161181111211 - 213 = 161181103019 is a prime.
It is a super-2 number, since 2×1611811112112 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (161181115211) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80590555605 + 80590555606.
It is an arithmetic number, because the mean of its divisors is an integer number (80590555606).
Almost surely, 2161181111211 is an apocalyptic number.
161181111211 is a deficient number, since it is larger than the sum of its proper divisors (1).
161181111211 is an equidigital number, since it uses as much as digits as its factorization.
161181111211 is an evil number, because the sum of its binary digits is even.
The product of its digits is 96, while the sum is 25.
Adding to 161181111211 its reverse (112111181161), we get a palindrome (273292292372).
The spelling of 161181111211 in words is "one hundred sixty-one billion, one hundred eighty-one million, one hundred eleven thousand, two hundred eleven".
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