1611813001 has 2 divisors, whose sum is σ = 1611813002. Its totient is φ = 1611813000.

The previous prime is 1611812957. The next prime is 1611813019. The reversal of 1611813001 is 1003181161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1359765625 + 252047376 = 36875^2 + 15876^2 .

It is an emirp because it is prime and its reverse (1003181161) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1611813001 is a prime.

It is not a weakly prime, because it can be changed into another prime (1611813031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 805906500 + 805906501.

It is an arithmetic number, because the mean of its divisors is an integer number (805906501).

Almost surely, 2^1611813001 is an apocalyptic number.

It is an amenable number.

1611813001 is a deficient number, since it is larger than the sum of its proper divisors (1).

1611813001 is an equidigital number, since it uses as much as digits as its factorization.

1611813001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 22.

The square root of 1611813001 is about 40147.3909613066. The cubic root of 1611813001 is about 1172.4784922474.

Adding to 1611813001 its reverse (1003181161), we get a palindrome (2614994162).

The spelling of 1611813001 in words is "one billion, six hundred eleven million, eight hundred thirteen thousand, one".