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16126004026313 is a prime number
BaseRepresentation
bin1110101010101010000010…
…1111011101101111001001
32010002122000221120112221222
43222222200233131233021
54103202024012320223
654144103423411425
73253031261405666
oct352524057355711
963078027515858
1016126004026313
115157aaa961405
1219853b2153b75
138cc8a254ac6c
143da707800a6d
151ce71b0120c8
hexeaaa0bddbc9

16126004026313 has 2 divisors, whose sum is σ = 16126004026314. Its totient is φ = 16126004026312.

The previous prime is 16126004026259. The next prime is 16126004026337. The reversal of 16126004026313 is 31362040062161.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12707321361289 + 3418682665024 = 3564733^2 + 1848968^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-16126004026313 is a prime.

It is not a weakly prime, because it can be changed into another prime (16126004026213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8063002013156 + 8063002013157.

It is an arithmetic number, because the mean of its divisors is an integer number (8063002013157).

Almost surely, 216126004026313 is an apocalyptic number.

It is an amenable number.

16126004026313 is a deficient number, since it is larger than the sum of its proper divisors (1).

16126004026313 is an equidigital number, since it uses as much as digits as its factorization.

16126004026313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 31104, while the sum is 35.

Adding to 16126004026313 its reverse (31362040062161), we get a palindrome (47488044088474).

The spelling of 16126004026313 in words is "sixteen trillion, one hundred twenty-six billion, four million, twenty-six thousand, three hundred thirteen".