161290412113 has 4 divisors (see below), whose sum is σ = 161413818480. Its totient is φ = 161167005748.

The previous prime is 161290412071. The next prime is 161290412123. The reversal of 161290412113 is 311214092161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 161290412113 - 2¹³ = 161290403921 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (161290412123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 61701223 + ... + 61703836.

It is an arithmetic number, because the mean of its divisors is an integer number (40353454620).

Almost surely, 2^161290412113 is an apocalyptic number.

It is an amenable number.

161290412113 is a deficient number, since it is larger than the sum of its proper divisors (123406367).

161290412113 is a wasteful number, since it uses less digits than its factorization.

161290412113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 123406366.

The product of its (nonzero) digits is 2592, while the sum is 31.

The spelling of 161290412113 in words is "one hundred sixty-one billion, two hundred ninety million, four hundred twelve thousand, one hundred thirteen".