Base | Representation |
---|---|
bin | 100100101011110100000011… |
… | …011001001010100000100011 |
3 | 210011021000001002100112102202 |
4 | 210223310003121022200203 |
5 | 132121400322332340111 |
6 | 1331050445401203415 |
7 | 45661316036201135 |
oct | 4453640331124043 |
9 | 704230032315382 |
10 | 161340503402531 |
11 | 4745413a03a262 |
12 | 16118a5419056b |
13 | 6c04462247b2b |
14 | 2bbacca0a1055 |
15 | 139bc8406ab3b |
hex | 92bd0364a823 |
161340503402531 has 2 divisors, whose sum is σ = 161340503402532. Its totient is φ = 161340503402530.
The previous prime is 161340503402453. The next prime is 161340503402567. The reversal of 161340503402531 is 135204305043161.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 161340503402531 - 214 = 161340503386147 is a prime.
It is a super-2 number, since 2×1613405034025312 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (161340503402581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80670251701265 + 80670251701266.
It is an arithmetic number, because the mean of its divisors is an integer number (80670251701266).
Almost surely, 2161340503402531 is an apocalyptic number.
161340503402531 is a deficient number, since it is larger than the sum of its proper divisors (1).
161340503402531 is an equidigital number, since it uses as much as digits as its factorization.
161340503402531 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 161340503402531 its reverse (135204305043161), we get a palindrome (296544808445692).
The spelling of 161340503402531 in words is "one hundred sixty-one trillion, three hundred forty billion, five hundred three million, four hundred two thousand, five hundred thirty-one".
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