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161358163403 is a prime number
BaseRepresentation
bin1001011001000110110…
…0100010110111001011
3120102111022211222221012
42112101230202313023
510120430142212103
6202043225234135
714441414521163
oct2262154426713
9512438758835
10161358163403
1162482527458
122733263294b
13122a675a8c8
147b4a0555a3
1542e5d1b2d8
hex2591b22dcb

161358163403 has 2 divisors, whose sum is σ = 161358163404. Its totient is φ = 161358163402.

The previous prime is 161358163387. The next prime is 161358163481. The reversal of 161358163403 is 304361853161.

161358163403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (304361853161) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 161358163403 - 24 = 161358163387 is a prime.

It is not a weakly prime, because it can be changed into another prime (161358163003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80679081701 + 80679081702.

It is an arithmetic number, because the mean of its divisors is an integer number (80679081702).

Almost surely, 2161358163403 is an apocalyptic number.

161358163403 is a deficient number, since it is larger than the sum of its proper divisors (1).

161358163403 is an equidigital number, since it uses as much as digits as its factorization.

161358163403 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 161358163403 in words is "one hundred sixty-one billion, three hundred fifty-eight million, one hundred sixty-three thousand, four hundred three".