1614071113 has 4 divisors (see below), whose sum is σ = 1615102720. Its totient is φ = 1613039508.

The previous prime is 1614071093. The next prime is 1614071209. The reversal of 1614071113 is 3111704161.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1614071113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1614071213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 513453 + ... + 516586.

It is an arithmetic number, because the mean of its divisors is an integer number (403775680).

Almost surely, 2^1614071113 is an apocalyptic number.

It is an amenable number.

1614071113 is a deficient number, since it is larger than the sum of its proper divisors (1031607).

1614071113 is a wasteful number, since it uses less digits than its factorization.

1614071113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1031606.

The product of its (nonzero) digits is 504, while the sum is 25.

The square root of 1614071113 is about 40175.5038922974. The cubic root of 1614071113 is about 1173.0257749884.

Adding to 1614071113 its reverse (3111704161), we get a palindrome (4725775274).

The spelling of 1614071113 in words is "one billion, six hundred fourteen million, seventy-one thousand, one hundred thirteen".