Base | Representation |
---|---|
bin | 1001011010001011100… |
… | …0000001000000101011 |
3 | 120110020102012002002112 |
4 | 2112202320001000223 |
5 | 10122022433230042 |
6 | 202132002552535 |
7 | 14451514405034 |
oct | 2264270010053 |
9 | 513212162075 |
10 | 161646383147 |
11 | 62610195197 |
12 | 273b306874b |
13 | 12321392732 |
14 | 7b7643da8b |
15 | 431129e982 |
hex | 25a2e0102b |
161646383147 has 2 divisors, whose sum is σ = 161646383148. Its totient is φ = 161646383146.
The previous prime is 161646383131. The next prime is 161646383189. The reversal of 161646383147 is 741383646161.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 161646383147 - 24 = 161646383131 is a prime.
It is a super-2 number, since 2×1616463831472 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 161646383095 and 161646383104.
It is not a weakly prime, because it can be changed into another prime (161646383117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 80823191573 + 80823191574.
It is an arithmetic number, because the mean of its divisors is an integer number (80823191574).
Almost surely, 2161646383147 is an apocalyptic number.
161646383147 is a deficient number, since it is larger than the sum of its proper divisors (1).
161646383147 is an equidigital number, since it uses as much as digits as its factorization.
161646383147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1741824, while the sum is 50.
The spelling of 161646383147 in words is "one hundred sixty-one billion, six hundred forty-six million, three hundred eighty-three thousand, one hundred forty-seven".
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