16204034131 has 2 divisors, whose sum is σ = 16204034132. Its totient is φ = 16204034130.

The previous prime is 16204034123. The next prime is 16204034201. The reversal of 16204034131 is 13143040261.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 16204034131 - 2³ = 16204034123 is a prime.

It is a super-2 number, since 2×16204034131² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 16204034096 and 16204034105.

It is not a weakly prime, because it can be changed into another prime (16204031131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8102017065 + 8102017066.

It is an arithmetic number, because the mean of its divisors is an integer number (8102017066).

Almost surely, 2^16204034131 is an apocalyptic number.

16204034131 is a deficient number, since it is larger than the sum of its proper divisors (1).

16204034131 is an equidigital number, since it uses as much as digits as its factorization.

16204034131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 16204034131 its reverse (13143040261), we get a palindrome (29347074392).

The spelling of 16204034131 in words is "sixteen billion, two hundred four million, thirty-four thousand, one hundred thirty-one".