Base | Representation |
---|---|
bin | 11110001111110000… |
… | …01110001101010011 |
3 | 1112220200020102100121 |
4 | 33013320032031103 |
5 | 231224001244011 |
6 | 11243151131111 |
7 | 1113254216245 |
oct | 170770161523 |
9 | 45820212317 |
10 | 16238306131 |
11 | 6983111813 |
12 | 3192213a97 |
13 | 16ba263088 |
14 | b00886095 |
15 | 6508b9e71 |
hex | 3c7e0e353 |
16238306131 has 2 divisors, whose sum is σ = 16238306132. Its totient is φ = 16238306130.
The previous prime is 16238306111. The next prime is 16238306171. The reversal of 16238306131 is 13160383261.
It is a weak prime.
It is an emirp because it is prime and its reverse (13160383261) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 16238306131 - 25 = 16238306099 is a prime.
It is a super-2 number, since 2×162383061312 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16238306111) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8119153065 + 8119153066.
It is an arithmetic number, because the mean of its divisors is an integer number (8119153066).
Almost surely, 216238306131 is an apocalyptic number.
16238306131 is a deficient number, since it is larger than the sum of its proper divisors (1).
16238306131 is an equidigital number, since it uses as much as digits as its factorization.
16238306131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 15552, while the sum is 34.
Adding to 16238306131 its reverse (13160383261), we get a palindrome (29398689392).
The spelling of 16238306131 in words is "sixteen billion, two hundred thirty-eight million, three hundred six thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •