Base | Representation |
---|---|
bin | 1110110001010011000100… |
… | …0010001101101001101011 |
3 | 2010111112112002000020010222 |
4 | 3230110301002031221223 |
5 | 4112034203031304323 |
6 | 54312332440000255 |
7 | 3264210445310015 |
oct | 354246102155153 |
9 | 63445462006128 |
10 | 16240094009963 |
11 | 51a142676579a |
12 | 19a353276008b |
13 | 90a5851b3c25 |
14 | 40204bc7d1b5 |
15 | 1d26972069c8 |
hex | ec53108da6b |
16240094009963 has 2 divisors, whose sum is σ = 16240094009964. Its totient is φ = 16240094009962.
The previous prime is 16240094009903. The next prime is 16240094010089. The reversal of 16240094009963 is 36990049004261.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16240094009963 - 228 = 16239825574507 is a prime.
It is a super-2 number, since 2×162400940099632 (a number of 27 digits) contains 22 as substring.
It is a Sophie Germain prime.
It is not a weakly prime, because it can be changed into another prime (16240094009903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8120047004981 + 8120047004982.
It is an arithmetic number, because the mean of its divisors is an integer number (8120047004982).
Almost surely, 216240094009963 is an apocalyptic number.
16240094009963 is a deficient number, since it is larger than the sum of its proper divisors (1).
16240094009963 is an equidigital number, since it uses as much as digits as its factorization.
16240094009963 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2519424, while the sum is 53.
The spelling of 16240094009963 in words is "sixteen trillion, two hundred forty billion, ninety-four million, nine thousand, nine hundred sixty-three".
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