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16240132433 = 74615032579
BaseRepresentation
bin11110001111111110…
…01100000101010001
31112220210200012120102
433013333030011101
5231224433214213
611243254222145
71113305563610
oct170777140521
945823605512
1016240132433
116984149958
123192954955
1316ba752425
14b00bdd877
15650b2b158
hex3c7fcc151

16240132433 has 8 divisors (see below), whose sum is σ = 18600415680. Its totient is φ = 13889915280.

The previous prime is 16240132423. The next prime is 16240132459. The reversal of 16240132433 is 33423104261.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 16240132433 - 212 = 16240128337 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 16240132396 and 16240132405.

It is not an unprimeable number, because it can be changed into a prime (16240132423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2513063 + ... + 2519516.

It is an arithmetic number, because the mean of its divisors is an integer number (2325051960).

Almost surely, 216240132433 is an apocalyptic number.

It is an amenable number.

16240132433 is a deficient number, since it is larger than the sum of its proper divisors (2360283247).

16240132433 is an equidigital number, since it uses as much as digits as its factorization.

16240132433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5033047.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 16240132433 its reverse (33423104261), we get a palindrome (49663236694).

The spelling of 16240132433 in words is "sixteen billion, two hundred forty million, one hundred thirty-two thousand, four hundred thirty-three".

Divisors: 1 7 461 3227 5032579 35228053 2320018919 16240132433