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16241250133553 is a prime number
BaseRepresentation
bin1110110001010111010111…
…1100011110011000110001
32010111122111122110101120012
43230111311330132120301
54112044040013233203
654313043255424305
73264251214223514
oct354256574363061
963448448411505
1016241250133553
1151a196a323535
1219a37b5985095
1390a70a885323
1440211b62ad7b
151d2713976bd8
hexec575f1e631

16241250133553 has 2 divisors, whose sum is σ = 16241250133554. Its totient is φ = 16241250133552.

The previous prime is 16241250133417. The next prime is 16241250133631. The reversal of 16241250133553 is 35533105214261.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 14447654214049 + 1793595919504 = 3801007^2 + 1339252^2 .

It is a cyclic number.

It is not a de Polignac number, because 16241250133553 - 210 = 16241250132529 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 16241250133553.

It is not a weakly prime, because it can be changed into another prime (16241250133853) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8120625066776 + 8120625066777.

It is an arithmetic number, because the mean of its divisors is an integer number (8120625066777).

Almost surely, 216241250133553 is an apocalyptic number.

It is an amenable number.

16241250133553 is a deficient number, since it is larger than the sum of its proper divisors (1).

16241250133553 is an equidigital number, since it uses as much as digits as its factorization.

16241250133553 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 324000, while the sum is 41.

The spelling of 16241250133553 in words is "sixteen trillion, two hundred forty-one billion, two hundred fifty million, one hundred thirty-three thousand, five hundred fifty-three".