Base | Representation |
---|---|
bin | 1001011101000111011… |
… | …0100000100010010010 |
3 | 120112021100012102200100 |
4 | 2113101312200202102 |
5 | 10130131214022023 |
6 | 202342115233230 |
7 | 14510164420545 |
oct | 2272166404222 |
9 | 515240172610 |
10 | 162434517138 |
11 | 629850609a3 |
12 | 27592ba8816 |
13 | 1241874c5ca |
14 | 7c0cd9a85c |
15 | 435a580c43 |
hex | 25d1da0892 |
162434517138 has 12 divisors (see below), whose sum is σ = 351941453838. Its totient is φ = 54144839040.
The previous prime is 162434517121. The next prime is 162434517151. The reversal of 162434517138 is 831715434261.
162434517138 is a `hidden beast` number, since 1 + 62 + 4 + 3 + 451 + 7 + 138 = 666.
It can be written as a sum of positive squares in only one way, i.e., 158988005289 + 3446511849 = 398733^2 + 58707^2 .
It is a super-2 number, since 2×1624345171382 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 162434517093 and 162434517102.
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 4512069903 + ... + 4512069938.
Almost surely, 2162434517138 is an apocalyptic number.
162434517138 is a gapful number since it is divisible by the number (18) formed by its first and last digit.
162434517138 is an abundant number, since it is smaller than the sum of its proper divisors (189506936700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
162434517138 is a wasteful number, since it uses less digits than its factorization.
162434517138 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9024139849 (or 9024139846 counting only the distinct ones).
The product of its digits is 483840, while the sum is 45.
The spelling of 162434517138 in words is "one hundred sixty-two billion, four hundred thirty-four million, five hundred seventeen thousand, one hundred thirty-eight".
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