Base | Representation |
---|---|
bin | 11110010000100101… |
… | …00001110111101011 |
3 | 1112221011012210021101 |
4 | 33020102201313223 |
5 | 231232232434121 |
6 | 11243555022231 |
7 | 1113366641104 |
oct | 171022416753 |
9 | 45834183241 |
10 | 16245202411 |
11 | 6986aa2019 |
12 | 319459a977 |
13 | 16bb809009 |
14 | b0175d3ab |
15 | 6512cd491 |
hex | 3c84a1deb |
16245202411 has 2 divisors, whose sum is σ = 16245202412. Its totient is φ = 16245202410.
The previous prime is 16245202313. The next prime is 16245202423. The reversal of 16245202411 is 11420254261.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16245202411 is a prime.
It is a super-3 number, since 3×162452024113 (a number of 32 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 16245202411.
It is not a weakly prime, because it can be changed into another prime (16245202481) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8122601205 + 8122601206.
It is an arithmetic number, because the mean of its divisors is an integer number (8122601206).
Almost surely, 216245202411 is an apocalyptic number.
16245202411 is a deficient number, since it is larger than the sum of its proper divisors (1).
16245202411 is an equidigital number, since it uses as much as digits as its factorization.
16245202411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3840, while the sum is 28.
Adding to 16245202411 its reverse (11420254261), we get a palindrome (27665456672).
The spelling of 16245202411 in words is "sixteen billion, two hundred forty-five million, two hundred two thousand, four hundred eleven".
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