Base | Representation |
---|---|
bin | 11110010000110011… |
… | …11101110110101011 |
3 | 1112221021212211122222 |
4 | 33020121331312223 |
5 | 231233232331133 |
6 | 11244104504255 |
7 | 1113422341133 |
oct | 171031756653 |
9 | 45837784588 |
10 | 16247152043 |
11 | 6988103891 |
12 | 319517b08b |
13 | 16bc03c545 |
14 | b01b09ac3 |
15 | 651565e98 |
hex | 3c867ddab |
16247152043 has 2 divisors, whose sum is σ = 16247152044. Its totient is φ = 16247152042.
The previous prime is 16247152027. The next prime is 16247152057. The reversal of 16247152043 is 34025174261.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 16247152043 - 24 = 16247152027 is a prime.
It is a super-3 number, since 3×162471520433 (a number of 32 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 16247151994 and 16247152012.
It is not a weakly prime, because it can be changed into another prime (16247151043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8123576021 + 8123576022.
It is an arithmetic number, because the mean of its divisors is an integer number (8123576022).
Almost surely, 216247152043 is an apocalyptic number.
16247152043 is a deficient number, since it is larger than the sum of its proper divisors (1).
16247152043 is an equidigital number, since it uses as much as digits as its factorization.
16247152043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 40320, while the sum is 35.
The spelling of 16247152043 in words is "sixteen billion, two hundred forty-seven million, one hundred fifty-two thousand, forty-three".
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