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162627139584067 is a prime number
BaseRepresentation
bin100100111110100010010100…
…111000101100000001000011
3210022211000001222022200002111
4210332202110320230001003
5132303440340213142232
61333513513200000151
746153265060245624
oct4476422470540103
9708730058280074
10162627139584067
11478aa867683884
12162a6290000057
136c9889a789782
142c232a4857a4b
1513c0489b26047
hex93e894e2c043

162627139584067 has 2 divisors, whose sum is σ = 162627139584068. Its totient is φ = 162627139584066.

The previous prime is 162627139583989. The next prime is 162627139584071. The reversal of 162627139584067 is 760485931726261.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-162627139584067 is a prime.

It is a super-2 number, since 2×1626271395840672 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 162627139583993 and 162627139584011.

It is not a weakly prime, because it can be changed into another prime (162627139584097) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81313569792033 + 81313569792034.

It is an arithmetic number, because the mean of its divisors is an integer number (81313569792034).

It is a 1-persistent number, because it is pandigital, but 2⋅162627139584067 = 325254279168134 is not.

Almost surely, 2162627139584067 is an apocalyptic number.

162627139584067 is a deficient number, since it is larger than the sum of its proper divisors (1).

162627139584067 is an equidigital number, since it uses as much as digits as its factorization.

162627139584067 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 182891520, while the sum is 67.

The spelling of 162627139584067 in words is "one hundred sixty-two trillion, six hundred twenty-seven billion, one hundred thirty-nine million, five hundred eighty-four thousand, sixty-seven".