Base | Representation |
---|---|
bin | 11110010110011010… |
… | …01011101011000001 |
3 | 1120001120021200121211 |
4 | 33023031023223001 |
5 | 231332244214132 |
6 | 11252503450121 |
7 | 1114532561143 |
oct | 171315135301 |
9 | 46046250554 |
10 | 16294132417 |
11 | 6a01681942 |
12 | 31a8a56941 |
13 | 16c89ab394 |
14 | b08058c93 |
15 | 655746147 |
hex | 3cb34bac1 |
16294132417 has 4 divisors (see below), whose sum is σ = 16294740400. Its totient is φ = 16293524436.
The previous prime is 16294132367. The next prime is 16294132429. The reversal of 16294132417 is 71423149261.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16294132417 is a prime.
It is a Duffinian number.
It is a self number, because there is not a number n which added to its sum of digits gives 16294132417.
It is not an unprimeable number, because it can be changed into a prime (16294132447) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 261843 + ... + 318040.
It is an arithmetic number, because the mean of its divisors is an integer number (4073685100).
Almost surely, 216294132417 is an apocalyptic number.
It is an amenable number.
16294132417 is a deficient number, since it is larger than the sum of its proper divisors (607983).
16294132417 is an equidigital number, since it uses as much as digits as its factorization.
16294132417 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 607982.
The product of its digits is 72576, while the sum is 40.
The spelling of 16294132417 in words is "sixteen billion, two hundred ninety-four million, one hundred thirty-two thousand, four hundred seventeen".
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