Base | Representation |
---|---|
bin | 100101000011111101111100… |
… | …111101000111011100000011 |
3 | 210101010200112011002221201122 |
4 | 211003331330331013130003 |
5 | 132331044304430342111 |
6 | 1334401203343222455 |
7 | 46222250604444431 |
oct | 4503757475073403 |
9 | 711120464087648 |
10 | 163000400246531 |
11 | 47a34099589111 |
12 | 163466a02a7a2b |
13 | 6cc4b44420ba3 |
14 | 2c3739366bd51 |
15 | 13ca033cc7cdb |
hex | 943f7cf47703 |
163000400246531 has 2 divisors, whose sum is σ = 163000400246532. Its totient is φ = 163000400246530.
The previous prime is 163000400246471. The next prime is 163000400246581. The reversal of 163000400246531 is 135642004000361.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-163000400246531 is a prime.
It is a super-2 number, since 2×1630004002465312 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 163000400246491 and 163000400246500.
It is not a weakly prime, because it can be changed into another prime (163000400246581) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81500200123265 + 81500200123266.
It is an arithmetic number, because the mean of its divisors is an integer number (81500200123266).
Almost surely, 2163000400246531 is an apocalyptic number.
163000400246531 is a deficient number, since it is larger than the sum of its proper divisors (1).
163000400246531 is an equidigital number, since it uses as much as digits as its factorization.
163000400246531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 51840, while the sum is 35.
Adding to 163000400246531 its reverse (135642004000361), we get a palindrome (298642404246892).
The spelling of 163000400246531 in words is "one hundred sixty-three trillion, four hundred million, two hundred forty-six thousand, five hundred thirty-one".
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