Base | Representation |
---|---|
bin | 1110110101100010110010… |
… | …0010011000011000111011 |
3 | 2010202111210022120212010012 |
4 | 3231120230202120120323 |
5 | 4114233042422004012 |
6 | 54410034235412135 |
7 | 3302402110432145 |
oct | 355305442303073 |
9 | 63674708525105 |
10 | 16313033000507 |
11 | 521a355937971 |
12 | 19b56a98b404b |
13 | 91440a4a1529 |
14 | 4057aad39c95 |
15 | 1d4515859622 |
hex | ed62c89863b |
16313033000507 has 2 divisors, whose sum is σ = 16313033000508. Its totient is φ = 16313033000506.
The previous prime is 16313033000497. The next prime is 16313033000521. The reversal of 16313033000507 is 70500033031361.
16313033000507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 16313033000507 - 24 = 16313033000491 is a prime.
It is a super-2 number, since 2×163130330005072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (16313033000557) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 8156516500253 + 8156516500254.
It is an arithmetic number, because the mean of its divisors is an integer number (8156516500254).
Almost surely, 216313033000507 is an apocalyptic number.
16313033000507 is a deficient number, since it is larger than the sum of its proper divisors (1).
16313033000507 is an equidigital number, since it uses as much as digits as its factorization.
16313033000507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17010, while the sum is 32.
Adding to 16313033000507 its reverse (70500033031361), we get a palindrome (86813066031868).
The spelling of 16313033000507 in words is "sixteen trillion, three hundred thirteen billion, thirty-three million, five hundred seven", and thus it is an aban number.
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