Base | Representation |
---|---|
bin | 100101000110000011101111… |
… | …010011011110111111000011 |
3 | 210101122102022112102022112201 |
4 | 211012003233103132333003 |
5 | 132340423004433233124 |
6 | 1334551202040334031 |
7 | 46235524465544365 |
oct | 4506035723367703 |
9 | 711572275368481 |
10 | 163144052633539 |
11 | 47a8a00561170a |
12 | 1636a4b1174317 |
13 | 70055588a5a13 |
14 | 2c402ddda4d35 |
15 | 13cdb404a8144 |
hex | 9460ef4defc3 |
163144052633539 has 2 divisors, whose sum is σ = 163144052633540. Its totient is φ = 163144052633538.
The previous prime is 163144052633489. The next prime is 163144052633557. The reversal of 163144052633539 is 935336250441361.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 163144052633539 - 213 = 163144052625347 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 163144052633539.
It is not a weakly prime, because it can be changed into another prime (163144058633539) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81572026316769 + 81572026316770.
It is an arithmetic number, because the mean of its divisors is an integer number (81572026316770).
Almost surely, 2163144052633539 is an apocalyptic number.
163144052633539 is a deficient number, since it is larger than the sum of its proper divisors (1).
163144052633539 is an equidigital number, since it uses as much as digits as its factorization.
163144052633539 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 20995200, while the sum is 55.
The spelling of 163144052633539 in words is "one hundred sixty-three trillion, one hundred forty-four billion, fifty-two million, six hundred thirty-three thousand, five hundred thirty-nine".
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