Base | Representation |
---|---|
bin | 1001100000110000101… |
… | …0000010011001111011 |
3 | 120121210111212001001122 |
4 | 2120030022002121323 |
5 | 10134132123341011 |
6 | 203023141335455 |
7 | 14543343106001 |
oct | 2301412023173 |
9 | 517714761048 |
10 | 163412715131 |
11 | 63337243596 |
12 | 2780670758b |
13 | 125432c50a3 |
14 | 7ca2c70a71 |
15 | 43b63a73db |
hex | 260c28267b |
163412715131 has 2 divisors, whose sum is σ = 163412715132. Its totient is φ = 163412715130.
The previous prime is 163412715097. The next prime is 163412715197. The reversal of 163412715131 is 131517214361.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 163412715131 - 226 = 163345606267 is a prime.
It is a super-2 number, since 2×1634127151312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 163412715091 and 163412715100.
It is not a weakly prime, because it can be changed into another prime (163412715031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81706357565 + 81706357566.
It is an arithmetic number, because the mean of its divisors is an integer number (81706357566).
Almost surely, 2163412715131 is an apocalyptic number.
163412715131 is a deficient number, since it is larger than the sum of its proper divisors (1).
163412715131 is an equidigital number, since it uses as much as digits as its factorization.
163412715131 is an evil number, because the sum of its binary digits is even.
The product of its digits is 15120, while the sum is 35.
Adding to 163412715131 its reverse (131517214361), we get a palindrome (294929929492).
The spelling of 163412715131 in words is "one hundred sixty-three billion, four hundred twelve million, seven hundred fifteen thousand, one hundred thirty-one".
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