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163540031012537 is a prime number
BaseRepresentation
bin100101001011110100100001…
…011101000111111010111001
3210110001021101221121011122112
4211023310201131013322321
5132413414440414400122
61335453130355302105
746306243265332004
oct4513644135077271
9713037357534575
10163540031012537
1148121a35032693
12164131a15aa935
1370339b2c9245a
142c55545dc653b
1513d90b8caa2e2
hex94bd21747eb9

163540031012537 has 2 divisors, whose sum is σ = 163540031012538. Its totient is φ = 163540031012536.

The previous prime is 163540031012509. The next prime is 163540031012543. The reversal of 163540031012537 is 735210130045361.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 121854465190441 + 41685565822096 = 11038771^2 + 6456436^2 .

It is a cyclic number.

It is not a de Polignac number, because 163540031012537 - 26 = 163540031012473 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 163540031012494 and 163540031012503.

It is not a weakly prime, because it can be changed into another prime (163540031012507) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 81770015506268 + 81770015506269.

It is an arithmetic number, because the mean of its divisors is an integer number (81770015506269).

Almost surely, 2163540031012537 is an apocalyptic number.

It is an amenable number.

163540031012537 is a deficient number, since it is larger than the sum of its proper divisors (1).

163540031012537 is an equidigital number, since it uses as much as digits as its factorization.

163540031012537 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 41.

Adding to 163540031012537 its reverse (735210130045361), we get a palindrome (898750161057898).

The spelling of 163540031012537 in words is "one hundred sixty-three trillion, five hundred forty billion, thirty-one million, twelve thousand, five hundred thirty-seven".