Base | Representation |
---|---|
bin | 100101001011110100100001… |
… | …011111001110110101000001 |
3 | 210110001021101222122020122121 |
4 | 211023310201133032311001 |
5 | 132413414441040040441 |
6 | 1335453130415204241 |
7 | 46306243303123021 |
oct | 4513644137166501 |
9 | 713037358566577 |
10 | 163540031565121 |
11 | 48121a3537a872 |
12 | 164131a1816681 |
13 | 70339b3126b23 |
14 | 2c555460cba81 |
15 | 13d90b8d68dd1 |
hex | 94bd217ced41 |
163540031565121 has 8 divisors (see below), whose sum is σ = 164371240725120. Its totient is φ = 162708833079408.
The previous prime is 163540031565089. The next prime is 163540031565133. The reversal of 163540031565121 is 121565130045361.
163540031565121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 163540031565121 - 25 = 163540031565089 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (163540031565191) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29004010 + ... + 34180588.
It is an arithmetic number, because the mean of its divisors is an integer number (20546405090640).
Almost surely, 2163540031565121 is an apocalyptic number.
It is an amenable number.
163540031565121 is a deficient number, since it is larger than the sum of its proper divisors (831209159999).
163540031565121 is a wasteful number, since it uses less digits than its factorization.
163540031565121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5337143.
The product of its (nonzero) digits is 324000, while the sum is 43.
The spelling of 163540031565121 in words is "one hundred sixty-three trillion, five hundred forty billion, thirty-one million, five hundred sixty-five thousand, one hundred twenty-one".
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