Base | Representation |
---|---|
bin | 10111110011001101011… |
… | …011001111010000000001 |
3 | 12210100121011211211222002 |
4 | 113303031123033100001 |
5 | 203244033203321423 |
6 | 3251204242353345 |
7 | 226110025656326 |
oct | 27631533172001 |
9 | 5710534754862 |
10 | 1635534042113 |
11 | 580698368244 |
12 | 224b8905b855 |
13 | bb2cb99086a |
14 | 59235ad0b4d |
15 | 2c825ea4228 |
hex | 17ccd6cf401 |
1635534042113 has 4 divisors (see below), whose sum is σ = 1638408443460. Its totient is φ = 1632659640768.
The previous prime is 1635534042101. The next prime is 1635534042167. The reversal of 1635534042113 is 3112404355361.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 754436427889 + 881097614224 = 868583^2 + 938668^2 .
It is a cyclic number.
It is not a de Polignac number, because 1635534042113 - 216 = 1635533976577 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (1635534042613) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1437199820 + ... + 1437200957.
It is an arithmetic number, because the mean of its divisors is an integer number (409602110865).
Almost surely, 21635534042113 is an apocalyptic number.
It is an amenable number.
1635534042113 is a deficient number, since it is larger than the sum of its proper divisors (2874401347).
1635534042113 is an equidigital number, since it uses as much as digits as its factorization.
1635534042113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2874401346.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 1635534042113 its reverse (3112404355361), we get a palindrome (4747938397474).
The spelling of 1635534042113 in words is "one trillion, six hundred thirty-five billion, five hundred thirty-four million, forty-two thousand, one hundred thirteen".
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