Base | Representation |
---|---|
bin | 100101001100111111111101… |
… | …111111111101001011000011 |
3 | 210110100000111122022200021112 |
4 | 211030333331333331023003 |
5 | 132421231342334324103 |
6 | 1335554245054513535 |
7 | 46315141626065243 |
oct | 4514777577751303 |
9 | 713300448280245 |
10 | 163621040542403 |
11 | 48153325881474 |
12 | 16426a2b5058ab |
13 | 703b5232c0002 |
14 | 2c5942cc6db23 |
15 | 13db25abddcd8 |
hex | 94cffdffd2c3 |
163621040542403 has 4 divisors (see below), whose sum is σ = 168899138624448. Its totient is φ = 158342942460360.
The previous prime is 163621040542397. The next prime is 163621040542411. The reversal of 163621040542403 is 304245040126361.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 163621040542403 - 26 = 163621040542339 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (163621040542493) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2639049040976 + ... + 2639049041037.
It is an arithmetic number, because the mean of its divisors is an integer number (42224784656112).
Almost surely, 2163621040542403 is an apocalyptic number.
163621040542403 is a deficient number, since it is larger than the sum of its proper divisors (5278098082045).
163621040542403 is an equidigital number, since it uses as much as digits as its factorization.
163621040542403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5278098082044.
The product of its (nonzero) digits is 414720, while the sum is 41.
Adding to 163621040542403 its reverse (304245040126361), we get a palindrome (467866080668764).
The spelling of 163621040542403 in words is "one hundred sixty-three trillion, six hundred twenty-one billion, forty million, five hundred forty-two thousand, four hundred three".
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