Base | Representation |
---|---|
bin | 10111110111100000101… |
… | …000101110101011100010 |
3 | 12210210111222001112001110 |
4 | 113313200220232223202 |
5 | 203333012214004442 |
6 | 3253250342444150 |
7 | 226332323064000 |
oct | 27674050565342 |
9 | 5723458045043 |
10 | 1640151313122 |
11 | 5826477262a3 |
12 | 225a57433656 |
13 | bb88644709a |
14 | 59553005a70 |
15 | 2c9e650969c |
hex | 17de0a2eae2 |
1640151313122 has 32 divisors (see below), whose sum is σ = 3825425808000. Its totient is φ = 468614660304.
The previous prime is 1640151313081. The next prime is 1640151313127. The reversal of 1640151313122 is 2213131510461.
It is a self number, because there is not a number n which added to its sum of digits gives 1640151313122.
It is not an unprimeable number, because it can be changed into a prime (1640151313127) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 398479797 + ... + 398483912.
It is an arithmetic number, because the mean of its divisors is an integer number (119544556500).
Almost surely, 21640151313122 is an apocalyptic number.
1640151313122 is an abundant number, since it is smaller than the sum of its proper divisors (2185274494878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1640151313122 is an equidigital number, since it uses as much as digits as its factorization.
1640151313122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 796963735 (or 796963721 counting only the distinct ones).
The product of its (nonzero) digits is 4320, while the sum is 30.
Adding to 1640151313122 its reverse (2213131510461), we get a palindrome (3853282823583).
The spelling of 1640151313122 in words is "one trillion, six hundred forty billion, one hundred fifty-one million, three hundred thirteen thousand, one hundred twenty-two".
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