164046113531 has 4 divisors (see below), whose sum is σ = 164359777752. Its totient is φ = 163732449312.

The previous prime is 164046113461. The next prime is 164046113587. The reversal of 164046113531 is 135311640461.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 164046113531 - 2²² = 164041919227 is a prime.

It is a super-2 number, since 2×164046113531² (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 164046113491 and 164046113500.

It is not an unprimeable number, because it can be changed into a prime (164046143531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156831326 + ... + 156832371.

It is an arithmetic number, because the mean of its divisors is an integer number (41089944438).

Almost surely, 2^164046113531 is an apocalyptic number.

164046113531 is a deficient number, since it is larger than the sum of its proper divisors (313664221).

164046113531 is an equidigital number, since it uses as much as digits as its factorization.

164046113531 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 313664220.

The product of its (nonzero) digits is 25920, while the sum is 35.

Adding to 164046113531 its reverse (135311640461), we get a palindrome (299357753992).

The spelling of 164046113531 in words is "one hundred sixty-four billion, forty-six million, one hundred thirteen thousand, five hundred thirty-one".