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1640525504281 is a prime number
BaseRepresentation
bin10111110111110110111…
…100001001111100011001
312210211111001011101211021
4113313312330021330121
5203334244012114111
63253351431002441
7226344515464216
oct27676674117431
95724431141737
101640525504281
11582819973694
12225b40809421
13bb915b20281
145958a9acb0d
152ca192c0d71
hex17df6f09f19

1640525504281 has 2 divisors, whose sum is σ = 1640525504282. Its totient is φ = 1640525504280.

The previous prime is 1640525504273. The next prime is 1640525504377. The reversal of 1640525504281 is 1824055250461.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1633092305625 + 7433198656 = 1277925^2 + 86216^2 .

It is a cyclic number.

It is not a de Polignac number, because 1640525504281 - 23 = 1640525504273 is a prime.

It is a super-2 number, since 2×16405255042812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1640525604281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 820262752140 + 820262752141.

It is an arithmetic number, because the mean of its divisors is an integer number (820262752141).

Almost surely, 21640525504281 is an apocalyptic number.

It is an amenable number.

1640525504281 is a deficient number, since it is larger than the sum of its proper divisors (1).

1640525504281 is an equidigital number, since it uses as much as digits as its factorization.

1640525504281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 384000, while the sum is 43.

The spelling of 1640525504281 in words is "one trillion, six hundred forty billion, five hundred twenty-five million, five hundred four thousand, two hundred eighty-one".