Base | Representation |
---|---|
bin | 11110100100101001… |
… | …01110101000111001 |
3 | 1120100212222210100021 |
4 | 33102110232220321 |
5 | 232103332114121 |
6 | 11312411210441 |
7 | 1120512611560 |
oct | 172224565071 |
9 | 46325883307 |
10 | 16413551161 |
11 | 6a63026a17 |
12 | 3220a46a21 |
13 | 1717660867 |
14 | b19c62bd7 |
15 | 660e84641 |
hex | 3d252ea39 |
16413551161 has 4 divisors (see below), whose sum is σ = 18758344192. Its totient is φ = 14068758132.
The previous prime is 16413551131. The next prime is 16413551173. The reversal of 16413551161 is 16115531461.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 16115531461 = 6481 ⋅2486581.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-16413551161 is a prime.
It is not an unprimeable number, because it can be changed into a prime (16413551131) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1172396505 + ... + 1172396518.
It is an arithmetic number, because the mean of its divisors is an integer number (4689586048).
Almost surely, 216413551161 is an apocalyptic number.
It is an amenable number.
16413551161 is a deficient number, since it is larger than the sum of its proper divisors (2344793031).
16413551161 is an equidigital number, since it uses as much as digits as its factorization.
16413551161 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2344793030.
The product of its digits is 10800, while the sum is 34.
It can be divided in two parts, 164135 and 51161, that added together give a square (215296 = 4642).
The spelling of 16413551161 in words is "sixteen billion, four hundred thirteen million, five hundred fifty-one thousand, one hundred sixty-one".
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