Base | Representation |
---|---|
bin | 1001100011101111100… |
… | …0101100111101010011 |
3 | 120200212022121222010011 |
4 | 2120323320230331103 |
5 | 10142302122232303 |
6 | 203234424415351 |
7 | 14602235345206 |
oct | 2307370547523 |
9 | 520768558104 |
10 | 164213477203 |
11 | 63708254a26 |
12 | 279aa917557 |
13 | 12640183ab9 |
14 | 7d3b35793d |
15 | 441183016d |
hex | 263be2cf53 |
164213477203 has 2 divisors, whose sum is σ = 164213477204. Its totient is φ = 164213477202.
The previous prime is 164213477179. The next prime is 164213477251. The reversal of 164213477203 is 302774312461.
It is a weak prime.
It is an emirp because it is prime and its reverse (302774312461) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-164213477203 is a prime.
It is a super-3 number, since 3×1642134772033 (a number of 35 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (164213477273) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82106738601 + 82106738602.
It is an arithmetic number, because the mean of its divisors is an integer number (82106738602).
Almost surely, 2164213477203 is an apocalyptic number.
164213477203 is a deficient number, since it is larger than the sum of its proper divisors (1).
164213477203 is an equidigital number, since it uses as much as digits as its factorization.
164213477203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 169344, while the sum is 40.
Adding to 164213477203 its reverse (302774312461), we get a palindrome (466987789664).
The spelling of 164213477203 in words is "one hundred sixty-four billion, two hundred thirteen million, four hundred seventy-seven thousand, two hundred three".
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