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164213477203 is a prime number
BaseRepresentation
bin1001100011101111100…
…0101100111101010011
3120200212022121222010011
42120323320230331103
510142302122232303
6203234424415351
714602235345206
oct2307370547523
9520768558104
10164213477203
1163708254a26
12279aa917557
1312640183ab9
147d3b35793d
15441183016d
hex263be2cf53

164213477203 has 2 divisors, whose sum is σ = 164213477204. Its totient is φ = 164213477202.

The previous prime is 164213477179. The next prime is 164213477251. The reversal of 164213477203 is 302774312461.

It is a weak prime.

It is an emirp because it is prime and its reverse (302774312461) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-164213477203 is a prime.

It is a super-3 number, since 3×1642134772033 (a number of 35 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (164213477273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 82106738601 + 82106738602.

It is an arithmetic number, because the mean of its divisors is an integer number (82106738602).

Almost surely, 2164213477203 is an apocalyptic number.

164213477203 is a deficient number, since it is larger than the sum of its proper divisors (1).

164213477203 is an equidigital number, since it uses as much as digits as its factorization.

164213477203 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 169344, while the sum is 40.

Adding to 164213477203 its reverse (302774312461), we get a palindrome (466987789664).

The spelling of 164213477203 in words is "one hundred sixty-four billion, two hundred thirteen million, four hundred seventy-seven thousand, two hundred three".