164311401156433 has 4 divisors (see below), whose sum is σ = 168132596532208. Its totient is φ = 160490205780660.

The previous prime is 164311401156431. The next prime is 164311401156451. The reversal of 164311401156433 is 334651104113461.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 164311401156433 - 2¹ = 164311401156431 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (43), and also a Moran number because the ratio is a prime number: 3821195375731 = 164311401156433 / (1 + 6 + 4 + 3 + 1 + 1 + 4 + 0 + 1 + 1 + 5 + 6 + 4 + 3 + 3).

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 164311401156433.

It is not an unprimeable number, because it can be changed into a prime (164311401156431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1910597687823 + ... + 1910597687908.

It is an arithmetic number, because the mean of its divisors is an integer number (42033149133052).

Almost surely, 2^{164311401156433} is an apocalyptic number.

It is an amenable number.

164311401156433 is a deficient number, since it is larger than the sum of its proper divisors (3821195375775).

164311401156433 is an equidigital number, since it uses as much as digits as its factorization.

164311401156433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3821195375774.

The product of its (nonzero) digits is 311040, while the sum is 43.

Adding to 164311401156433 its reverse (334651104113461), we get a palindrome (498962505269894).

The spelling of 164311401156433 in words is "one hundred sixty-four trillion, three hundred eleven billion, four hundred one million, one hundred fifty-six thousand, four hundred thirty-three".