16431452131 has 4 divisors (see below), whose sum is σ = 16434062064. Its totient is φ = 16428842200.

The previous prime is 16431452123. The next prime is 16431452173. The reversal of 16431452131 is 13125413461.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13125413461 = 211 ⋅62205751.

It is a cyclic number.

It is not a de Polignac number, because 16431452131 - 2³ = 16431452123 is a prime.

It is a super-2 number, since 2×16431452131² (a number of 21 digits) contains 22 as substring.

It is a Smith number, since the sum of its digits (31) coincides with the sum of the digits of its prime factors. Since it is squarefree, it is also a hoax number.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 16431452093 and 16431452102.

It is not an unprimeable number, because it can be changed into a prime (16431402131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1295500 + ... + 1308121.

It is an arithmetic number, because the mean of its divisors is an integer number (4108515516).

Almost surely, 2^16431452131 is an apocalyptic number.

16431452131 is a deficient number, since it is larger than the sum of its proper divisors (2609933).

16431452131 is an equidigital number, since it uses as much as digits as its factorization.

16431452131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2609932.

The product of its digits is 8640, while the sum is 31.

Adding to 16431452131 its reverse (13125413461), we get a palindrome (29556865592).

The spelling of 16431452131 in words is "sixteen billion, four hundred thirty-one million, four hundred fifty-two thousand, one hundred thirty-one".