Base | Representation |
---|---|
bin | 11110100110110111… |
… | …11100011111010001 |
3 | 1120102012010021022221 |
4 | 33103123330133101 |
5 | 232123122020423 |
6 | 11314315301041 |
7 | 1121130365161 |
oct | 172333743721 |
9 | 46365107287 |
10 | 16432220113 |
11 | 6a72618201 |
12 | 322714a781 |
13 | 171b49918a |
14 | b1c5225a1 |
15 | 662920e5d |
hex | 3d36fc7d1 |
16432220113 has 4 divisors (see below), whose sum is σ = 16432657648. Its totient is φ = 16431782580.
The previous prime is 16432220099. The next prime is 16432220131. The reversal of 16432220113 is 31102223461.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31102223461 = 31 ⋅1003297531.
It is a cyclic number.
It is not a de Polignac number, because 16432220113 - 229 = 15895349201 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (16432220713) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156531 + ... + 239512.
It is an arithmetic number, because the mean of its divisors is an integer number (4108164412).
Almost surely, 216432220113 is an apocalyptic number.
It is an amenable number.
16432220113 is a deficient number, since it is larger than the sum of its proper divisors (437535).
16432220113 is an equidigital number, since it uses as much as digits as its factorization.
16432220113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 437534.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 16432220113 its reverse (31102223461), we get a palindrome (47534443574).
The spelling of 16432220113 in words is "sixteen billion, four hundred thirty-two million, two hundred twenty thousand, one hundred thirteen".
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